(2x-5)(3x^2-4x+1)=0

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Solution for (2x-5)(3x^2-4x+1)=0 equation:


Simplifying
(2x + -5)(3x2 + -4x + 1) = 0

Reorder the terms:
(-5 + 2x)(3x2 + -4x + 1) = 0

Reorder the terms:
(-5 + 2x)(1 + -4x + 3x2) = 0

Multiply (-5 + 2x) * (1 + -4x + 3x2)
(-5(1 + -4x + 3x2) + 2x * (1 + -4x + 3x2)) = 0
((1 * -5 + -4x * -5 + 3x2 * -5) + 2x * (1 + -4x + 3x2)) = 0
((-5 + 20x + -15x2) + 2x * (1 + -4x + 3x2)) = 0
(-5 + 20x + -15x2 + (1 * 2x + -4x * 2x + 3x2 * 2x)) = 0
(-5 + 20x + -15x2 + (2x + -8x2 + 6x3)) = 0

Reorder the terms:
(-5 + 20x + 2x + -15x2 + -8x2 + 6x3) = 0

Combine like terms: 20x + 2x = 22x
(-5 + 22x + -15x2 + -8x2 + 6x3) = 0

Combine like terms: -15x2 + -8x2 = -23x2
(-5 + 22x + -23x2 + 6x3) = 0

Solving
-5 + 22x + -23x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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